Submission #2501757


Source Code Expand

//#include <ext/pb_ds/assoc_container.hpp> // Common file
//#include <ext/pb_ds/tree_policy.hpp> // Including tree_order_statistics_node_update
//#include <ext/pb_ds/detail/standard_policies.hpp>
#include<set>
#include<map>
#include <unordered_map>
#include <unordered_set>
#include<list>
#include<iomanip>
#include<cmath>
#include<string>
#include<vector>
#include<queue>
#include<stack>
#include<complex>
#include<sstream>
#include<iostream>
#include<fstream>
#include<algorithm>
#include<numeric>
#include<utility>
#include<functional>
#include<stdio.h>
#include<assert.h>
#include<memory.h>
#include<bitset>
#include<math.h>
#include <strings.h>
#include <fstream>


#define f first
#define s second
#define pb push_back
#define lp(i,a,n) for(int (i)=(a);(i)<=(int)(n);(i)++)
#define lpd(i,n,a) for(int (i)=(n);(i)>=(a);--(i))
#define mp make_pair
#define clr(a, b) memset(a,b,sizeof a)
#define all(v) v.begin(),v.end()
#define mod 1000000007
#define eps 1e-8
#define infi 2e9
#define infll 1e18
#define MX 1000000
#define X real()
#define Y imag()
#define polar(r,t) ((r)* exp(point(0,(t))))
#define length(a) hypot( (a).X , (a).Y )
#define angle(a) atan2( (a).Y , (a).X )
#define vec(a,b) ( (b) - (a) )
#define dot(a,b) (conj(a)*(b)).X
#define cross(a,b) (conj(a)*(b)).Y
#define lengthsqr(a) dot(a,a)
#define reflect(V,M) (conj((V)/(M)) * (M))
//#define rotate(a, theta) (a) * (polar(1.0, (theta) ))
#define normalize(a)   ((a)/length(a))
#define ccw(a,b,c) cross(vec(a,b) , vec(a,c)) > eps
#define cosRule(a,b,c) (acos(((a)*(a)+(b)*(b)-(c)*(c))/(2*(a)*(b))))
#define cosDot(a,b) (acos(dot(a,b)/length(a)/length(b)))
#define EQ(a,b) (fabs((a) - (b)) <= eps) /* equal to */
#define NE(a,b) (fabs((a) - (b)) > eps)  /* not equal to */
#define LT(a,b) ((a) < (b) - eps)        /* less than */
#define GT(a,b) ((a) > (b) + eps)        /* greater than */
#define LE(a,b) ((a) <= (b) + eps)       /* less than or equal to */
#define GE(a,b) ((a) >= (b) - eps)       /* greater than or equal to */
#define mod1 100050001
#define mod2 100030001
#define base1 37
#define base2 31
#define PI acos(-1)
#define sz(a) (int) (a).size()

using namespace std;
typedef long long ll;
typedef pair<int, int> pii;
typedef pair<double,double> pdd;
typedef pair<ll, ll> pll;
typedef vector<int> vi;
typedef vector<ll> vll;
typedef vector<vi> vvi;
typedef set<int> si;
typedef map<int, int> mii;
typedef complex<long double> point;
typedef pair<point, point> line;
typedef pair<double , point> Circle;
typedef long double ld;


const int N = 5005, ALPHA = 28;

struct trie {
    map<int,trie*> childs;
    int siz = 0;
    
    trie(){
        siz = 0;
    };
    
    
    int insert(char *S) {
        siz = max(siz, 1);
        if(*S == '\0') return 0;
        
        int p =  *S - 'a', ret = 0;
        if(!childs.count(p)) childs[p] = new trie(), ++ret;
        
        ret += childs[p] -> insert(S+1);
        siz += ret;
        return ret;
    }
    
    void calc_siz () {
        siz = 1;
        lp(i, 0, ALPHA-1) if(childs[i]) {
            childs[i]->calc_siz();
            siz += childs[i]->siz;
        }
        
    }


    
    
    void search(string &ans,int k) {
        
        if(!k) return;
        
        lp(i, 0, ALPHA-1) if(childs[i]) {
            if(childs[i]->siz < k)
                k -= childs[i]->siz;
            else{
                ans += i+'a', childs[i]->search(ans, k-1);
                return;
            }
            
        }
        
    }
    
    
};


unsigned char mask[] = { 0x80, 0x40, 0x20, 0x10, 0x08, 0x04, 0x02, 0x01 };
#define tget(i) ( (t[(i)/8]&mask[(i)%8]) ? 1 : 0 )
#define tset(i, b) t[(i)/8]=(b) ? (mask[(i)%8]|t[(i)/8]) : ((~mask[(i)%8])&t[(i)/8])
#define chr(i) (cs==sizeof(int)?((int*)s)[i]:((unsigned char *)s)[i])
#define isLMS(i) (i>0 && tget(i) && !tget(i-1))

// find the start or end of each bucket
void getBuckets(unsigned char *s, int *bkt, int n, int K, int cs, bool end) {
    int i, sum = 0;
    for (i = 0; i <= K; i++)
        bkt[i] = 0; // clear all buckets
    for (i = 0; i < n; i++)
        bkt[chr(i)]++; // compute the size of each bucket
    for (i = 0; i <= K; i++) {
        sum += bkt[i];
        bkt[i] = end ? sum : sum - bkt[i];
    }
}
// compute SAl
void induceSAl(unsigned char *t, int *SA, unsigned char *s, int *bkt, int n, int K, int cs, bool end) {
    int i, j;
    getBuckets(s, bkt, n, K, cs, end); // find starts of buckets
    for (i = 0; i < n; i++) {
        j = SA[i] - 1;
        if (j >= 0 && !tget(j))
            SA[bkt[chr(j)]++] = j;
    }
}
// compute SAs
void induceSAs(unsigned char *t, int *SA, unsigned char *s, int *bkt, int n, int K, int cs, bool end) {
    int i, j;
    getBuckets(s, bkt, n, K, cs, end); // find ends of buckets
    for (i = n - 1; i >= 0; i--) {
        j = SA[i] - 1;
        if (j >= 0 && tget(j))
            SA[--bkt[chr(j)]] = j;
    }
}

// find the suffix array SA of s[0..n-1] in {1..K}^n
// require s[n-1]=0 (the sentinel!), n>=2
// use a working space (excluding s and SA) of at most 2.25n+O(1) for a constant alphabet
void SA_IS(unsigned char *s, int *SA, int n, int K, int cs) {
    int i, j;
    unsigned char *t = (unsigned char *) malloc(n / 8 + 1); // LS-type array in bits
    // Classify the type of each character
    tset(n-2, 0);
    tset(n-1, 1); // the sentinel must be in s1, important!!!
    for (i = n - 3; i >= 0; i--)
        tset(i, (chr(i)<chr(i+1) || (chr(i)==chr(i+1) && tget(i+1)==1))?1:0);
    // stage 1: reduce the problem by at least 1/2
    // sort all the S-substrings
    int *bkt = (int *) malloc(sizeof(int) * (K + 1)); // bucket array
    getBuckets(s, bkt, n, K, cs, true); // find ends of buckets
    for (i = 0; i < n; i++)
        SA[i] = -1;
    for (i = 1; i < n; i++)
        if (isLMS(i))
            SA[--bkt[chr(i)]] = i;
    induceSAl(t, SA, s, bkt, n, K, cs, false);
    induceSAs(t, SA, s, bkt, n, K, cs, true);
    free(bkt);
    // compact all the sorted substrings into the first n1 items of SA
    // 2*n1 must be not larger than n (proveable)
    int n1 = 0;
    for (i = 0; i < n; i++)
        if (isLMS(SA[i]))
            SA[n1++] = SA[i];
    // find the lexicographic names of all substrings
    for (i = n1; i < n; i++)
        SA[i] = -1; // init the name array buffer
    int name = 0, prev = -1;
    for (i = 0; i < n1; i++) {
        int pos = SA[i];
        bool diff = false;
        for (int d = 0; d < n; d++)
            if (prev == -1 || chr(pos+d) != chr(prev+d) || tget(pos+d) != tget(prev+d)) {
                diff = true;
                break;
            } else if (d > 0 && (isLMS(pos+d) || isLMS(prev+d)))
                break;
        if (diff) {
            name++;
            prev = pos;
        }
        pos = (pos % 2 == 0) ? pos / 2 : (pos - 1) / 2;
        SA[n1 + pos] = name - 1;
    }
    for (i = n - 1, j = n - 1; i >= n1; i--)
        if (SA[i] >= 0)
            SA[j--] = SA[i];
    // stage 2: solve the reduced problem
    // recurse if names are not yet unique
    int *SA1 = SA, *s1 = SA + n - n1;
    if (name < n1)
        SA_IS((unsigned char*) s1, SA1, n1, name - 1, sizeof(int));
    else
        // generate the suffix array of s1 directly
        for (i = 0; i < n1; i++)
            SA1[s1[i]] = i;
    // stage 3: induce the result for the original problem
    bkt = (int *) malloc(sizeof(int) * (K + 1)); // bucket array
    // put all left-most S characters into their buckets
    getBuckets(s, bkt, n, K, cs, true); // find ends of buckets
    for (i = 1, j = 0; i < n; i++)
        if (isLMS(i))
            s1[j++] = i; // get p1
    for (i = 0; i < n1; i++)
        SA1[i] = s1[SA1[i]]; // get index in s
    for (i = n1; i < n; i++)
        SA[i] = -1; // init SA[n1..n-1]
    for (i = n1 - 1; i >= 0; i--) {
        j = SA[i];
        SA[i] = -1;
        SA[--bkt[chr(j)]] = j;
    }
    induceSAl(t, SA, s, bkt, n, K, cs, false);
    induceSAs(t, SA, s, bkt, n, K, cs, true);
    free(bkt);
    free(t);
}

int sa[N];
int lcp[N];
int Rank[N];
unsigned char *s;

void calc_lcp() {
    //compute the rank of each suffix
    for (int i = 0; i - 1 < 0 || s[i - 1]; i++)
        Rank[sa[i]] = i;
    
    int c = 0;  // the length of lcp between i and j
    for (int i = 0; i - 1 < 0 || s[i - 1]; i++) {
        if (Rank[i]) {  //if i is not the first suffix in the sorted array
            int j = sa[Rank[i] - 1];  //find the element before i and name it j
            while (s[i + c] == s[j + c])
                c++;  //count the number of shared chars
        }
        lcp[Rank[i]] = c;  //store the result in lcp array
        if (c)
            c--;  //Decrement c by one because length of lcp of i+1 is c-1
    }
}


//
//int main() {
//    string str = "abcab";
//    n = sz(str);
//    s = (unsigned char*) str.c_str();
//    SA_IS(s, sa, n + 1, 256, 1);
//    calc_lcp();
//    
//    
//    
//    
//}


int n,k;
char str[N];
trie tr;
vi ind[ALPHA];



void print(string str) {
    for (int i = 0; i < n; i++) {
        cout << str.substr(sa[i + 1]);
        if (i < n - 1)
            cout << " " << lcp[i + 1];
        cout << endl;
    }
}

int main() {
    
    scanf("%s%d",str,&k);
    s = (unsigned char *)string(str).c_str();
    n = (int) strlen(str);

    SA_IS(s, sa, n + 1, 256, 1);
    calc_lcp();
    
    lp(i, 0, min(2*k,n)) {
        tr.insert(str+sa[i]);
    }
    
    string ans;
    tr.search(ans, k);
    
    printf("%s\n",ans.c_str());
    return 0;
}

Submission Info

Submission Time
Task C - K-th Substring
User AhmedAbdellah
Language C++14 (GCC 5.4.1)
Score 0
Code Size 9780 Byte
Status RE
Exec Time 346 ms
Memory 256 KB

Compile Error

./Main.cpp: In function ‘int main()’:
./Main.cpp:322:25: warning: ignoring return value of ‘int scanf(const char*, ...)’, declared with attribute warn_unused_result [-Wunused-result]
     scanf("%s%d",str,&k);
                         ^

Judge Result

Set Name Sample Subtask All
Score / Max Score 0 / 0 0 / 200 0 / 100
Status
AC × 2
WA × 1
AC × 9
WA × 2
AC × 9
WA × 4
RE × 6
Set Name Test Cases
Sample 0_000.txt, 0_001.txt, 0_002.txt
Subtask 0_000.txt, 0_001.txt, 0_002.txt, 1_003.txt, 1_004.txt, 1_005.txt, 1_006.txt, 1_007.txt, 1_008.txt, 1_009.txt, 1_010.txt
All 0_000.txt, 0_001.txt, 0_002.txt, 1_003.txt, 1_004.txt, 1_005.txt, 1_006.txt, 1_007.txt, 1_008.txt, 1_009.txt, 1_010.txt, 2_011.txt, 2_012.txt, 2_013.txt, 2_014.txt, 2_015.txt, 2_016.txt, 2_017.txt, 2_018.txt
Case Name Status Exec Time Memory
0_000.txt AC 1 ms 256 KB
0_001.txt WA 1 ms 256 KB
0_002.txt AC 1 ms 256 KB
1_003.txt AC 1 ms 256 KB
1_004.txt AC 1 ms 256 KB
1_005.txt AC 1 ms 256 KB
1_006.txt AC 1 ms 256 KB
1_007.txt AC 1 ms 256 KB
1_008.txt AC 1 ms 256 KB
1_009.txt WA 1 ms 256 KB
1_010.txt AC 1 ms 256 KB
2_011.txt WA 2 ms 256 KB
2_012.txt WA 2 ms 256 KB
2_013.txt RE 346 ms 256 KB
2_014.txt RE 101 ms 256 KB
2_015.txt RE 103 ms 256 KB
2_016.txt RE 101 ms 256 KB
2_017.txt RE 101 ms 256 KB
2_018.txt RE 100 ms 256 KB